{"id":527,"date":"2019-12-09T14:08:36","date_gmt":"2019-12-09T12:08:36","guid":{"rendered":"http:\/\/skolarbbos.net\/?p=527"},"modified":"2019-12-22T18:17:17","modified_gmt":"2019-12-22T16:17:17","slug":"oktalni-sistem-brojeva","status":"publish","type":"post","link":"https:\/\/skolarbbos.net\/?p=527","title":{"rendered":"Oktalni sistem brojeva"},"content":{"rendered":"<p>Oktalni sistem brojeva ima osnovu broj 8 i koristi cifre 0, 1, 2, 3, 4, 5, 6 i 7. Svaka cifra dekadnog sistema brojeva ima svoju te\u017einu koja je predstavljena stepenom broja 8 i to se prikazuje kao 8<sup>i<\/sup>, gde je eksponent i ceo broj i njegova vrednost je odre\u0111ena polo\u017eajem cifre u samom broju.<\/p>\n<p><strong>Pretvaranje oktalnog broja u dekadni <\/strong><\/p>\n<p>Procedura za pretvaranje oktalnog broja 37<sub>8<\/sub> u dekadni je slede\u0107a:<\/p>\n<p>37<sub>8<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 = 3 \u00b78<sup>1<\/sup> + 7\u00b78<sup>0<\/sup> =<\/p>\n<p>= 24 + 7 =<\/p>\n<p>= 31<sub>10<\/sub><\/p>\n<p>Evo jo\u0161 dva primera. Treba pretvoriti brojeve 142<sub>8<\/sub> i 364<sub>8<\/sub> u dekadne. Postupak za pretvaranje broja 142<sub>8<\/sub> u dekadni je slede\u0107i:<\/p>\n<p>142<sub>8<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 = 1 \u00b78<sup>2<\/sup> +4\u00b78<sup>1<\/sup> +2\u00b78<sup>0<\/sup> =<\/p>\n<p>= 64 + 32 + 2 =<\/p>\n<p>= 98<sub>10<\/sub><\/p>\n<p>Postupak za pretvaranje broja 364<sub>8<\/sub> u dekadni je slede\u0107i:<\/p>\n<p>364<sub>8<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 = 3 \u00b78<sup>2<\/sup> +6\u00b78<sup>1<\/sup> +4\u00b78<sup>0<\/sup> =<br \/>\n= 192 + 48 + 4 =<\/p>\n<p>= 244<sub>10<\/sub><\/p>\n<p>&nbsp;<\/p>\n<p><strong>Pretvaranje oktalnog broja u binarni <\/strong><\/p>\n<p>Ovo je vrlo jednostavno pretvaranje i zbog toga se oktalni sistem brojeva koristi za skra\u0107eni prikaz binarnih brojeva. Sve \u0161to treba da se uradi je da se svaka oktalna cifra prika\u017ee sa 3 bita. Procedura za pretvaranje oktalnog broja 76543<sub>8<\/sub> u binarni je slede\u0107a:<\/p>\n<p>76543<sub>8<\/sub> = 111 110 101 100 011<\/p>\n<p>7\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 3 \u00a0 \u2192 1<\/p>\n<p>3 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 1 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Ovo pi\u0161emo kao 111<\/p>\n<p>1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 1<\/p>\n<p>&nbsp;<\/p>\n<p>6\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 3 \u00a0 \u2192 0<\/p>\n<p>3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Ovo pi\u0161emo kao 110<\/p>\n<p>1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0 \u00a0 \u2192 1<\/p>\n<p>&nbsp;<\/p>\n<p>5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2 \u00a0 \u2192 1<\/p>\n<p>2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Ovo pi\u0161emo kao 101<\/p>\n<p>1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0 \u00a0 \u2192 1<\/p>\n<p>&nbsp;<\/p>\n<p>4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2 \u00a0 \u2192 0<\/p>\n<p>2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0Ovo pi\u0161emo kao 100<\/p>\n<p>1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0 \u00a0 \u2192 1<\/p>\n<p>&nbsp;<\/p>\n<p>3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1 \u00a0 \u2192 1<\/p>\n<p>1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0 \u00a0 \u2192 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Ovo pi\u0161emo kao 011<\/p>\n<p>S obzirom da treba da imamo 3 broj ispred prve jedinice dodajemo 0. Pa je 3 u binarnom sistemu 011.<\/p>\n<p>Pa je broj 76543<sub>8<\/sub> \u00a0= 111110101100011<sub>2<\/sub>.<\/p>\n<p><strong>Pretvaranje oktalnog broja u heksadekadni <\/strong><\/p>\n<p>Postupak pretvaranja oktalnog broja u heksadekadni je slede\u0107i. Najpre oktalni broj pretvorimo u binarni pa onda taj binarni broj pretvorimo u heksadekadni. Na primer, ako uzmemo prethodni broj 76543<sub>8<\/sub> , taj broj smo pretvorili u binarni i ima slede\u0107i oblik 111110101100011<sub>2<\/sub>. Sada je potrebno da ovaj broj (111110101100011<sub>2<\/sub>) pretvorimo u heksadekadni. Zna\u010di delimo na 4 cifre od desne na levu stranu.<\/p>\n<p>111110101100011<sub>2 <\/sub>= \u00a00111 1101 0110 0011<\/p>\n<p>0111\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0 0 * 2<sup>3<\/sup> + 1 * 2<sup>2<\/sup> + 1 * 2<sup>1<\/sup> + 1 * 2<sup>0<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 7<\/p>\n<p>1101\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0 1 * 2<sup>3<\/sup> + 1 * 2<sup>2<\/sup> + 0 * 2<sup>1<\/sup> + 1 * 2<sup>0<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 13 (D)<\/p>\n<p>0110\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0 0 * 2<sup>3<\/sup> + 1 * 2<sup>2<\/sup> + 1 * 2<sup>1<\/sup> + 0 * 2<sup>0<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 6<\/p>\n<p>0011\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0 0 * 2<sup>3<\/sup> + 0 * 2<sup>2<\/sup> + 1 * 2<sup>1<\/sup> + 1 * 2<sup>0<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 3<\/p>\n<p>&nbsp;<\/p>\n<p>Pa broj 76543<sub>8<\/sub> pretvoren u heksadekadni ima slede\u0107i oblik 7D63<sub>16<\/sub>.<\/p>\n","protected":false},"excerpt":{"rendered":"Oktalni sistem brojeva ima osnovu broj 8 i koristi cifre 0, 1,<a class=\"moretag\" href=\"https:\/\/skolarbbos.net\/?p=527\"> &lt;b&gt;[Nastavi sa \u010ditanjem...]&lt;\/b&gt;<\/a>","protected":false},"author":1,"featured_media":537,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[18],"tags":[],"class_list":["post-527","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-binarni-sistemi"],"_links":{"self":[{"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/posts\/527","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=527"}],"version-history":[{"count":2,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/posts\/527\/revisions"}],"predecessor-version":[{"id":1381,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/posts\/527\/revisions\/1381"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=\/wp\/v2\/media\/537"}],"wp:attachment":[{"href":"https:\/\/skolarbbos.net\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=527"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=527"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/skolarbbos.net\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=527"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}